How to show a button with condition in PHP

Scenario: Let’s say we have “Get Details” and “Update Details” buttons. And we want to make visible Update button after we fire the “Get Details” button.

This is Get Details button:

<input type="submit" value="Get Details" name="getDetails" />

Then Update Details button must be like that:

<input type="submit" name='updateButton' value='updateDetails' <?php if(isset($_POST['getDetails'])) {?> style="visibility:visible" <?php } else { ?> style="visibility:hidden" <?php } ?> />

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